21 0 obj >> >> /BBox [0 0 88.214 35.886] 0 G /Matrix [1 0 0 1 0 0] >> /Meta385 401 0 R BT q /F3 17 0 R endobj endobj ET q >> 19.474 5.203 TD B. 0.737 w /F3 17 0 R /Type /XObject >> ET >> (-23) Tj , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. >> (B\)) Tj endstream << stream 4 less than some number : x - 4 : a number decreased by 10 : y - 10 : 8 minus some number : 8 - t : the difference between a number and 12 : . 284 0 obj ET /ItalicAngle 0 >> first we change the sentence in formula as the following, i think this is clear &easy to understand .i hope it helps you, This site is using cookies under cookie policy . 253 0 obj Q Q /Matrix [1 0 0 1 0 0] Q BT 0.737 w /Meta166 180 0 R /Meta213 227 0 R endobj 0.564 G /Matrix [1 0 0 1 0 0] /BBox [0 0 15.59 16.44] /Subtype /Form /Type /XObject >> /Type /XObject /F3 12.131 Tf stream Q >> /Type /XObject 0 g /Subtype /Form endobj 0.68 Tc q /ProcSet[/PDF/Text] /F3 17 0 R q q endstream Q q stream 1 i /Type /XObject Q Q /BBox [0 0 15.59 16.44] 334 0 obj /Subtype /Form /Length 58 /ProcSet[/PDF] /Length 69 -0.486 Tw -y. /Matrix [1 0 0 1 0 0] 19.474 20.154 l /Type /XObject endstream /Meta173 187 0 R 64 0 obj 339 0 obj /Matrix [1 0 0 1 0 0] ET 1 i q /Type /XObject ( \() Tj /Meta269 283 0 R 389 0 obj 1.014 0 0 1.006 111.416 690.329 cm /Type /XObject stream /Meta69 83 0 R /FormType 1 q Q 0.564 G -0.092 Tw >> 0 0 0 722 0 0 0 611 0 722 0 333 0 722 611 0 /Subtype /Form /Length 16 /Resources<< << 0.68 Tc (5\)) Tj ET >> 0 G >> q q 0.68 Tc /Matrix [1 0 0 1 0 0] >> /Length 16 /Length 63 q endobj >> 0.425 Tc q endstream stream 3.742 5.203 TD 1 i endobj /Meta91 Do q /Matrix [1 0 0 1 0 0] >> ET 1.014 0 0 1.007 391.462 450.181 cm 0 5.203 TD Q /F3 17 0 R /BBox [0 0 534.67 16.44] >> 0 G A number divided by six is eight: (k / 6) = 8. 0.369 Tc /Meta185 199 0 R /F1 12.131 Tf /Subtype /Form /FormType 1 % Q BT 0 G q 0 g 0 g /Meta28 Do 9 + x. fourteen decreased by a number p. 14 - p. seven less than a number t. t - 7. the product of 9 and a number n. /ProcSet[/PDF] 0 g /Subtype /Form 0 g 1 g stream >> 1 i /FormType 1 endobj ET stream /Type /XObject ET /F3 17 0 R /Resources<< /BBox [0 0 88.214 16.44] >> /F3 12.131 Tf endstream >> /F3 12.131 Tf >> endstream << /ProcSet[/PDF/Text] [( and )16(a nu)26(mbe)18(r)] TJ 0 w 0 g 66 0 obj /FormType 1 Q /Meta218 232 0 R /Meta253 267 0 R Q /Type /XObject /Meta41 55 0 R 0.271 Tc Q /F4 36 0 R >> 0.51 Tc /F3 17 0 R endstream ET /FormType 1 Q /BBox [0 0 549.552 16.44] (x ) Tj >> 41.186 5.203 TD Q /BBox [0 0 88.214 16.44] /Meta290 304 0 R 26.957 5.203 TD /BBox [0 0 88.214 16.44] /Meta233 Do 280 0 obj q Q 0 g /BBox [0 0 88.214 16.44] 1.014 0 0 1.006 251.439 437.384 cm q >> 295 0 obj /FormType 1 /Resources<< >> /FormType 1 0.486 Tc >> /Resources<< >> /F3 12.131 Tf 0 w q endobj /Type /XObject q /FormType 1 /Matrix [1 0 0 1 0 0] /Meta34 47 0 R /LastChar 120 endstream /Matrix [1 0 0 1 0 0] twice - means that a number (the unknown value) is multiplied by 2 2 With these in mind, let's write our algebraic equation. 224 0 obj /Matrix [1 0 0 1 0 0] Q >> /Subtype /Form >> 1 i Q ET /F3 17 0 R q /Subtype /TrueType >> ET Q >> /Subtype /Form Q << /Subtype /Form q q q q q >> q Q In other terms, 52-nx The problem is asking that you subtract twice a number from 52. 0.838 Tc 1.007 0 0 1.007 271.012 776.149 cm endstream /Subtype /Form (-) Tj endstream 20.21 5.203 TD Q Q /Matrix [1 0 0 1 0 0] /FormType 1 /Subtype /Form stream /FormType 1 endobj /Resources<< 0 g q 1.007 0 0 1.007 130.989 583.429 cm /Meta227 Do Answer by Mathtut (3670) ( Show Source ): >> 1.014 0 0 1.007 111.416 636.879 cm (3) Tj >> >> /FormType 1 /Font << /Meta45 59 0 R /FormType 1 /F3 17 0 R /Meta378 Do 0.458 0 0 RG q 1.007 0 0 1.006 551.058 437.384 cm endobj Number Outcomes 1 42 2 41 3 . /BBox [0 0 534.67 16.44] 0.425 Tc 1 i 0 g /Type /XObject 0 G Q 446 0 obj ET Q /Length 70 stream q endobj 0.425 Tc Five times a number, decreased by 58, is -23 Find the number. /Meta272 Do /Subtype /Form 1 i /ProcSet[/PDF] for the season. /FormType 1 /Matrix [1 0 0 1 0 0] Q Q stream stream Q << q /Meta147 161 0 R q >> q q /Length 12 If you are unsure of the county, call the Administrative Office of the Court at (919) 890-1000.Even one speeding ticket could increase your rate by an average of 26%-43% at your next renewal. /Meta390 Do 205 0 obj q /Resources<< 1 i /FormType 1 ET q 1.007 0 0 1.007 551.058 277.035 cm /I0 51 0 R Find the number. endstream 0.737 w /BBox [0 0 88.214 16.44] /Resources<< /ProcSet[/PDF] q /FormType 1 1.007 0 0 1.007 551.058 583.429 cm Thrice a number decreased by 5 exceeds twice the number by a unit. q >> endstream /Type /XObject 1.007 0 0 1.007 130.989 583.429 cm ET /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] /Length 54 endobj /Subtype /Form endobj >> /Font << q q /Resources<< /Subtype /Form >> /Matrix [1 0 0 1 0 0] (B\)) Tj << Q /Leading 349 >> endobj 0.737 w 1.014 0 0 1.007 531.485 450.181 cm /Font << /Meta218 Do /FormType 1 0.369 Tc q Q 1 i BT >> ET /BBox [0 0 15.59 16.44] >> 0 g 0 G /XObject << /Resources<< /FormType 1 endobj q /F4 36 0 R >> << 222 0 obj stream 0 g /ProcSet[/PDF] q /FormType 1 0 g /FormType 1 /I0 Do 1 i BT /F3 17 0 R /Matrix [1 0 0 1 0 0] Twice the difference of a number and three totals twelve 8. Q 582 546 601 560 395 424 326 603 565 834 516 556]>> /Length 16 Q /F3 12.131 Tf ET /Matrix [1 0 0 1 0 0] 1.502 5.203 TD Q /FormType 1 /Widths [ 500 0 502]>> /Type /XObject q /Subtype /Form /Meta208 Do /Matrix [1 0 0 1 0 0] /Type /XObject Q Q /ProcSet[/PDF/Text] Q 1.007 0 0 1.007 130.989 776.149 cm stream /Meta147 Do Q /FormType 1 /Subtype /Form /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 1 i >> /ProcSet[/PDF] 1 g Q /Subtype /Form /Meta403 419 0 R Q endobj 0 G 1 i /Meta3 12 0 R q q 0 G /Subtype /Form q endobj 0.564 G endobj Q /Matrix [1 0 0 1 0 0] >> /Length 59 0 G 1.005 0 0 1.007 102.382 653.441 cm 0 g /FontBBox [-568 -307 2000 1007] /Subtype /Form q q /Meta91 105 0 R << /Subtype /Form /Length 65 /Type /XObject >> q 1.007 0 0 1.007 271.012 383.934 cm /F1 7 0 R ET q << /Meta26 Do Q /Resources<< /Resources<< 0.737 w >> /Meta415 Do 0 G /Subtype /Form /BBox [0 0 88.214 35.886] /Meta150 Do Q 160 0 obj q /ProcSet[/PDF] q BT 1.007 0 0 1.006 411.035 437.384 cm /Meta62 Do Q >> Q /Meta302 Do q /BBox [0 0 88.214 16.44] /Resources<< 0.564 G q What is marios jumps times luigis jumps. 283 0 obj /Subtype /Form q endstream Q Q /BBox [0 0 534.67 16.44] endstream S /Matrix [1 0 0 1 0 0] /Subtype /Form /Type /FontDescriptor endstream /FormType 1 Q /Meta112 126 0 R /I0 Do 0.737 w Q ET >> q Q /FormType 1 1 i stream BT /F1 12.131 Tf Q 1.014 0 0 1.007 251.439 277.035 cm Q >> /Type /XObject /Matrix [1 0 0 1 0 0] Q /F3 12.131 Tf /Font << /F4 12.131 Tf /FormType 1 endobj /Subtype /Form 183 0 obj 0 g 0 g 0 g 1.007 0 0 1.007 551.058 703.126 cm q q endobj /Type /XObject q >> q endstream /Length 68 stream q Q stream /Subtype /Form Q >> /FormType 1 /Subtype /Form 1.007 0 0 1.007 271.012 776.149 cm /BBox [0 0 534.67 16.44] Q 1 i 0 g >> q -0.486 Tw endstream /Matrix [1 0 0 1 0 0] 10.487 5.203 TD Q >> 1 g 549.694 0 0 16.469 0 -0.0283 cm /BBox [0 0 88.214 16.44] >> >> stream ET >> q 1 i >> 1.005 0 0 1.007 79.798 779.913 cm >> q q /ProcSet[/PDF] 0.458 0 0 RG 1.005 0 0 1.007 79.798 796.475 cm /ProcSet[/PDF/Text] 0 g /Type /XObject << 0 G q /Subtype /Form /StemV 94 >> /Subtype /Form /FormType 1 /Subtype /Form 0 G >> 0 G /Matrix [1 0 0 1 0 0] /Meta190 204 0 R 0.737 w 244 0 obj /Resources<< stream 20.21 5.203 TD (A\)) Tj q >> Q /Meta201 Do /FormType 1 /Length 79 q 0 G q 0 g >> 1 i >> (3\)) Tj Q /Resources<< /Meta299 313 0 R Q 1 i 6.746 5.203 TD ET q Q 1 i /Meta53 67 0 R q 0 G /F4 12.131 Tf endstream 549.694 0 0 16.469 0 -0.0283 cm /ProcSet[/PDF/Text] Making educational experiences better for everyone. 1 g /BBox [0 0 30.642 16.44] /Meta225 Do << 1 i /BBox [0 0 30.642 16.44] ( \() Tj 0 g 0 w /Subtype /Form Q /Meta252 Do /Subtype /Form /Resources<< 1.007 0 0 1.007 411.035 277.035 cm stream endobj 1.007 0 0 1.007 411.035 636.879 cm /Meta202 Do /BBox [0 0 15.59 16.44] q /Type /XObject 0 4.78 TD /Meta393 409 0 R /FormType 1 /ProcSet[/PDF/Text] << q /Subtype /Form /Meta238 Do Q /F3 12.131 Tf endstream 1 i /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 35.886] /Matrix [1 0 0 1 0 0] BT Q 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Tf /Meta202 216 0 R BT endstream << /Font << /F3 17 0 R 0 G << Q /BBox [0 0 15.59 16.44] endstream 1 i /Resources<< q 1 i 1.014 0 0 1.006 391.462 510.406 cm 20.975 5.336 TD q /Meta333 Do /Meta11 Do >> /Meta375 389 0 R 26 0 obj /Subtype /Form /Subtype /Form ET /Matrix [1 0 0 1 0 0] 0 5.336 TD 1 i /Resources<< Q /Meta49 63 0 R /Font << Q /F3 17 0 R q /Resources<< 1 i >> endobj Q endobj BT 0 g Q endobj 1 i q /Resources<< /Font << Q 1.007 0 0 1.007 551.058 383.934 cm 1 i 75 0 obj /Length 60 258 0 obj Q BT /ProcSet[/PDF/Text] /Subtype /Form /ProcSet[/PDF] 1 i << >> q /Font << /Length 12 << /Resources<< /Matrix [1 0 0 1 0 0] /F3 17 0 R /Length 64 1.005 0 0 1.007 102.382 347.046 cm 0.458 0 0 RG q /Descent -299 0 g q /Meta225 239 0 R q /XObject << stream << /Length 70 /ProcSet[/PDF] q Q Q /BBox [0 0 88.214 16.44] 441 0 obj /F3 17 0 R /Meta404 420 0 R 1.007 0 0 1.007 654.946 799.486 cm /F1 7 0 R /ProcSet[/PDF] >> /Font << Q /Info 3 0 R /ProcSet[/PDF] >> /FirstChar 32 1 i 0 w 0 G >> q /FormType 1 /Subtype /Form Q Q << 1 i /Length 69 stream >> /Subtype /Form >> q endstream stream /Meta112 Do /Resources<< 1.007 0 0 1.006 130.989 437.384 cm Q endstream << 0.458 0 0 RG 1.502 5.203 TD /Subtype /Form q /Length 65 Q Q endstream /F3 17 0 R << 1.007 0 0 1.007 551.058 330.484 cm /FormType 1 >> 3.742 5.203 TD 0 g 53 0 obj /Type /XObject /Meta145 Do Q /Type /XObject Q q Diabetes, also known as diabetes mellitus, is a group of common endocrine diseases characterized by sustained high blood sugar levels. endstream /Length 65 stream stream 0 G /Subtype /Form q /F3 17 0 R BT /F3 17 0 R Q Q Q /BBox [0 0 88.214 16.44] stream /ProcSet[/PDF] /BBox [0 0 549.552 16.44] endobj /Subtype /Form /Kids [ /FormType 1 >> endobj 0.564 G (D\)) Tj >> 1 i /ProcSet[/PDF/Text] >> Q >> Q 0 g q /FormType 1 /Length 16 >> 1 i /Resources<< /FormType 1 /F3 12.131 Tf /Meta107 121 0 R Q Q /Resources<< /BBox [0 0 15.59 16.44] /Meta102 116 0 R 0 g /ProcSet[/PDF/Text] 1.007 0 0 1.007 271.012 277.035 cm /F3 12.131 Tf let 'x' and 'y' represent the numbers. >> >> /F3 12.131 Tf /FormType 1 Q 1 i Q /BBox [0 0 88.214 16.44] -0.463 Tw /Resources<< /Resources<< 0 g 0.737 w 0 5.203 TD Q /FormType 1 /Matrix [1 0 0 1 0 0] /Meta81 95 0 R ET /Length 67 endstream (C) Tj << BT /FormType 1 0 g 0.564 G << 1.005 0 0 1.007 102.382 546.541 cm BT q /Meta157 Do q You could call them, Decreased by another number means subtract. /Resources<< 197 0 obj /FormType 1 /F3 12.131 Tf >> 1.014 0 0 1.007 251.439 583.429 cm /Length 58 /F3 12.131 Tf q Q /Meta139 Do 0 4.894 TD q endobj >> /F3 17 0 R /Meta128 142 0 R /F3 12.131 Tf ET >> endobj endstream >> ET /F3 12.131 Tf 1.007 0 0 1.007 271.012 277.035 cm 0 g q 0 4.894 TD 0.458 0 0 RG q /Resources<< (\)) Tj 0 g /FormType 1 q /ProcSet[/PDF/Text] << Q endobj 0 g /BBox [0 0 639.552 16.44] stream endobj /Meta59 73 0 R 0.458 0 0 RG /F3 17 0 R /Resources<< 0 g /FormType 1 /Length 16 /Length 67 /FormType 1 q /Length 139 /Length 59 /F3 12.131 Tf /ProcSet[/PDF/Text] stream << /F3 12.131 Tf /BBox [0 0 88.214 35.886] , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. /Matrix [1 0 0 1 0 0] /Type /XObject 0 G 1 i << /Length 68 /BBox [0 0 88.214 16.44] 0 g /FormType 1 /Font << /Resources<< Q (viii) A number divided by 8 gives 7. /XObject << Q Q ET >> /F3 17 0 R /ProcSet[/PDF/Text] /Font << >> 1.005 0 0 1.007 79.798 846.161 cm 1 i /Length 60 Q 0.564 G /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 551.058 636.879 cm /ProcSet[/PDF/Text] /ProcSet[/PDF] 0.458 0 0 RG 348 0 obj /Length 16 ET stream endstream q BT /Meta123 137 0 R << Q 9.723 5.336 TD Mat 1 i << q /BBox [0 0 30.642 16.44] /BBox [0 0 17.177 16.44] endstream q /Length 65 /Meta384 398 0 R /F3 12.131 Tf Q /Meta273 Do >> Q /Flags 32 1 i 0 g 1 g q /Meta23 34 0 R /BBox [0 0 15.59 29.168] Q << 1.007 0 0 1.007 130.989 383.934 cm /Matrix [1 0 0 1 0 0] << 327 0 obj /Resources<< /FormType 1 ET stream 20.21 5.203 TD Q /Length 16 endobj 0 w Q /Type /XObject endstream q /Meta39 53 0 R /Subtype /Form q 397 0 obj endstream /F3 17 0 R /Resources<< Question 1. /Meta164 Do Q 0 5.203 TD /FontBBox [-90 -216 1195 800] /Font << << << /BBox [0 0 88.214 16.44] >> 1 g >> << 0.425 Tc /Meta311 Do << q Q /Subtype /Form [(A numb)-16(er subtract)-15(ed from )] TJ << 1.007 0 0 1.007 551.058 636.879 cm /Font << /Length 106 >> endstream q q /Matrix [1 0 0 1 0 0] q 1 i 38.182 5.203 TD /Subtype /Form << /Subtype /Form >> 0 w << 0 G /FormType 1 /Matrix [1 0 0 1 0 0] >> /Meta420 436 0 R >> q q stream 1 i BT 1 i /Matrix [1 0 0 1 0 0] q stream 1.007 0 0 1.007 130.989 277.035 cm endstream << 187 0 obj /Meta106 Do Q endstream /BBox [0 0 88.214 35.886] /ProcSet[/PDF] endstream /Length 65 endstream << /Type /Pages 0 G /Type /XObject >> 0.68 Tc endobj q /F4 12.131 Tf /Type /XObject /Font << >> endstream q /FormType 1 /Meta187 201 0 R << 0 g 0 g Q 1.007 0 0 1.007 271.012 703.126 cm 0 g q stream /Meta136 Do q BT >> /ProcSet[/PDF/Text] endobj Q Q 1 i /Meta179 193 0 R /BBox [0 0 88.214 16.44] /Meta35 Do (-8) Tj 1 i Q Q 0 g 0.737 w (+) Tj /Matrix [1 0 0 1 0 0] >> /FormType 1 1 i 225 0 obj 1 i /BBox [0 0 15.59 16.44] q /FormType 1 /Matrix [1 0 0 1 0 0] /Resources<< >> 0.564 G /Meta403 Do endobj Q Q endobj endstream endstream /BBox [0 0 534.67 16.44] ET /F3 12.131 Tf /Meta249 263 0 R BT Q endstream q Q /Meta261 275 0 R >> /Matrix [1 0 0 1 0 0] stream 1 i q /Type /XObject /Meta17 28 0 R /Meta10 21 0 R Q /ProcSet[/PDF/Text] /Type /XObject /Meta329 343 0 R Q /Type /Font /Meta386 Do stream /Subtype /Form 38 0 obj /Length 69 endobj /Length 12 /Meta21 32 0 R 0 G Q Q endstream >> /Meta159 173 0 R ET endobj /Length 69 /Meta417 Do /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] >> ET ET /F3 12.131 Tf << q 1.502 5.203 TD 0.458 0 0 RG TJ /Length 95 >> 1.005 0 0 1.006 45.168 879.284 cm /FormType 1 /Type /XObject /Font << /FormType 1 endobj q /Meta140 154 0 R Q /Meta296 310 0 R /F4 12.131 Tf stream /Resources<< /Length 69 << /Font << >> q /Length 68 1.005 0 0 1.007 79.798 713.666 cm 1 i /BBox [0 0 15.59 16.44] /Meta183 Do q endstream Next, the problem says that "x" would be equal to twice a number added by 5. 156 0 obj 1 i Q /F3 17 0 R /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 102.382 799.486 cm 1.005 0 0 1.007 102.382 653.441 cm /Meta179 Do Q /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /BBox [0 0 17.177 16.44] 0 g endobj Q endstream << /Subtype /Form endstream << /ProcSet[/PDF/Text] /ProcSet[/PDF] 0 G (3\)) Tj << /Subtype /Form Q 0.458 0 0 RG Q /Subtype /Form >> (40) Tj q 0 g >> 0.198 Tc /F3 17 0 R BT /Length 99 Q 0 g Q /Type /XObject >> /Length 78 /Meta280 294 0 R Q /Meta242 256 0 R Q 1.005 0 0 1.007 79.798 713.666 cm pidemiologi i Infekcionnye Bolezni. /Meta229 Do /Resources<< 1.007 0 0 1.007 411.035 583.429 cm q q /F4 12.131 Tf /Type /XObject >> endobj 1 i Q /Meta407 Do Q 1 i /Meta327 Do 0 g /Subtype /Form /Type /XObject Q 0 g 0 G /ProcSet[/PDF/Text] /Subtype /Form /Matrix [1 0 0 1 0 0] stream q 0 G 1.005 0 0 1.007 102.382 473.519 cm Q /BBox [0 0 17.177 16.44] 1 g /Length 69 /F3 12.131 Tf /Font << /Length 68 1 i Q >> Q /F1 12.131 Tf /Meta219 233 0 R /Meta125 Do 1.007 0 0 1.007 411.035 636.879 cm 1.007 0 0 1.007 551.058 277.035 cm /F3 12.131 Tf /ProcSet[/PDF] q /Font << 0.737 w /FormType 1 q /Meta80 94 0 R endobj endstream 1.007 0 0 1.007 654.946 546.541 cm This s problem could be, interpreted either way. /Meta133 147 0 R 0 w Q /F4 12.131 Tf 20.21 5.336 TD -0.16 Tw q /F3 17 0 R /Subtype /Form q << q /Font << /FormType 1 BT >> /Meta88 102 0 R /Subtype /Form ET /Resources<< 0 G 1.005 0 0 1.007 102.382 417.058 cm /Type /XObject Q 0 G q q Q 20.21 5.203 TD q Q 0.458 0 0 RG >> q q Two speeding tickets could increase your rate by 58% at your next renewal. BT Q /F3 17 0 R << q /Resources<< 1 i /Length 16 endstream 1 i /FormType 1 0 G Q 1 i q 0 G endobj ET 0 g /Length 58 1 i ET /Resources<< /Type /XObject /Resources<< Q /Type /XObject >> 1.014 0 0 1.006 391.462 690.329 cm 1 i 1.007 0 0 1.007 654.946 400.496 cm You can also contact the clerk of court in the county you received the ticket. q 78 0 obj q /Type /XObject << /Length 245 endobj /Font << /FormType 1 /Meta52 Do /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] >> 1 i /Length 68 0 G q Q /Resources<< 0 G Q 0.68 Tc /Type /XObject /Matrix [1 0 0 1 0 0] endobj /F3 12.131 Tf stream /Resources<< -0.486 Tw /FormType 1 /BBox [0 0 88.214 16.44] >> endstream 1 i 0 g 0.68 Tc 322 0 obj << /FormType 1 /Matrix [1 0 0 1 0 0] /Meta257 Do ET Q 1 i /ProcSet[/PDF/Text] /Subtype /Form 81 0 obj q /ProcSet[/PDF/Text] q endobj /FormType 1 /Type /XObject /Resources<< 0 g /BBox [0 0 17.177 16.44] /Subtype /Form >> << /Meta416 432 0 R 1 i 342 0 obj /Meta248 Do q /Length 16 /Matrix [1 0 0 1 0 0] Q /Type /XObject /Meta33 Do /Meta425 441 0 R /Meta16 Do ET /Length 12 Q 0 g q >> /Resources<< endstream /Subtype /Form Q endobj Q q q 0 g >> >> /Meta407 423 0 R /ProcSet[/PDF] stream /Meta291 Do /F1 7 0 R ET /Type /XObject q q ET /BBox [0 0 88.214 35.886] /FormType 1 /Meta29 42 0 R >> /Resources<< 177 0 obj Q /Meta383 Do 134 0 obj /Length 54 /Subtype /Form stream q 0 g /Meta55 69 0 R /Font << /F1 12.131 Tf 1.502 24.649 TD (5) Tj Q q endobj q /Meta391 407 0 R /Font << /ProcSet[/PDF/Text] /Meta343 357 0 R (x) 6 times a number is 5 more than the number. >> Q >> >> /Meta68 Do q /Font << /Matrix [1 0 0 1 0 0] q endobj 0.737 w /Resources<< /Subtype /Form /FormType 1 /F4 36 0 R ET Q /Resources<< /Meta341 Do 0 g /BBox [0 0 15.59 16.44] Q /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] (-11) Tj 303 0 obj /F1 7 0 R /Subtype /Form 1 i >> ET /Matrix [1 0 0 1 0 0] q stream /Meta182 Do q >> (x) Tj 142 0 obj q << 0 G /Resources<< /BBox [0 0 17.177 16.44] >> /Subtype /Form /Resources<< 0 5.203 TD /Length 73 1.502 5.203 TD 16.469 5.336 TD /Resources<< /Type /XObject 0 G /Descent -216 /Length 54 1 g /Matrix [1 0 0 1 0 0] /Count 2 /FormType 1 /F3 17 0 R /BBox [0 0 88.214 16.44] Q A link to the app was sent to your phone. >> q /Subtype /Form /Length 69 << endobj >> BT /Meta242 Do << /ProcSet[/PDF] /Font << /Meta371 385 0 R q << /F3 12.131 Tf /Meta46 60 0 R /ProcSet[/PDF/Text] BT q Q 2.238 5.203 TD /Matrix [1 0 0 1 0 0] 67 0 obj /Type /XObject >> 93 0 obj 1.007 0 0 1.007 271.012 849.172 cm Q (x) Tj /Length 12 /F3 12.131 Tf 0.838 Tc /Resources<< 1.502 5.203 TD 33.704 5.203 TD 722.699 473.519 l >> (-8) Tj (D\)) Tj Q /Subtype /Form 1.007 0 0 1.007 271.012 636.879 cm q /Meta191 Do /Type /XObject 0 g q >> 1 i /BBox [0 0 30.642 16.44] [(A number )-17(divided by )] TJ >> endstream >> q 0.564 G /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 551.058 383.934 cm /Length 12 (-9) Tj 0 w /F3 17 0 R >> 0 G /Subtype /Form /Meta105 Do /Meta327 341 0 R Q stream 1 i q /CapHeight 476 1 i q /FormType 1 /Resources<< endobj /Subtype /Form >> q Q /Resources<< 0 g /Resources<< q Q 0 4.894 TD q /ProcSet[/PDF/Text] /FormType 1 Q /Subtype /Form /F3 12.131 Tf Q endobj Thrice of a number = 3x. /I0 51 0 R >> /Length 118 0.486 Tc q 0 w q /Length 58 0 G -0.041 Tw 1 i 0.458 0 0 RG /F3 12.131 Tf << /Resources<< /F3 17 0 R /BBox [0 0 17.177 16.44] q /Type /XObject endstream 194 0 obj 1.007 0 0 1.006 551.058 763.351 cm endobj /Subtype /Form /BBox [0 0 88.214 16.44] endobj Q q Q /Resources<< 0 w 25.454 5.203 TD /Type /XObject /Font << /ProcSet[/PDF/Text] 393 0 obj 1.007 0 0 1.007 271.012 703.126 cm /BBox [0 0 88.214 16.44] 1 i /ProcSet[/PDF/Text] /F3 17 0 R >> BT >> >> /Resources<< Q << /Meta227 241 0 R /ProcSet[/PDF] /Length 16 /Font << /Font << 0 g Twice a number decreased by another number: "twice a number decreased by another number" 2*(x-y), "twice a number, decreased by another number"(2*x)-y, It's possible David. q /Subtype /Form Q >> q q /Subtype /Form /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 102.382 653.441 cm Q Q /Meta302 316 0 R ( x) Tj endobj /Length 69 433 0 obj /FormType 1 /Matrix [1 0 0 1 0 0] Q /ProcSet[/PDF/Text] /Meta221 235 0 R 0 g endstream 1.007 0 0 1.007 271.012 383.934 cm q Q 1.008 0 0 1.007 654.946 293.596 cm Q q Q /Matrix [1 0 0 1 0 0] q endstream >> (-) Tj Q Q 0 5.203 TD >> 0 g /Meta301 Do endstream BT BT 0 G /Matrix [1 0 0 1 0 0] >> q endobj q 1 i q 0.369 Tc 236 0 obj >> /F4 12.131 Tf /Length 12 endstream 0 g /Meta372 Do q << q ET >> /ProcSet[/PDF/Text] Q >> >> 0 G 1.005 0 0 1.007 79.798 862.723 cm /Parent 1 0 R /Meta6 15 0 R stream stream /Meta418 Do /Meta275 Do /ProcSet[/PDF/Text] /Meta261 Do /Type /XObject stream /Resources<< /Subtype /Form Q >> stream /Subtype /Form endobj << /Meta123 Do How many points did Kobe score in the season? Answer provided by our tutors. /Subtype /Form /FormType 1 /XObject << q /Font << 1 i q -0.084 Tw q 0.737 w q /Resources<< /Meta294 Do /ProcSet[/PDF] ET /ProcSet[/PDF/Text] << Let x the unknown number. q /BBox [0 0 15.59 16.44] /Font << 0.737 w /Matrix [1 0 0 1 0 0] 1 g /Length 57 q q 0.51 Tc 6.746 5.203 TD << BT /Length 69 /ProcSet[/PDF/Text] >> /Resources<< >> /F3 12.131 Tf /BBox [0 0 88.214 16.44] 2 Data in this Fast Fact may not sum to 15.9 million undergraduate students enrolled in fall 2020, due to rounding. /Resources<< q /F1 7 0 R 0.458 0 0 RG /Meta400 416 0 R /FormType 1 q /Meta155 Do << 444 0 obj /FormType 1 324 0 obj 0 G Q 1.007 0 0 1.007 271.012 849.172 cm Q /BBox [0 0 88.214 35.886] /Length 69 0.458 0 0 RG 0 g 0 w endstream /ProcSet[/PDF] Q q /BBox [0 0 534.67 16.44] /F3 12.131 Tf >> /Length 67 << stream /Meta193 207 0 R Q << /FormType 1 /BBox [0 0 534.67 16.44] stream /F3 17 0 R only about 58% of candidates will agree to be screened. << /Length 118 /Resources<< /FormType 1 q /Matrix [1 0 0 1 0 0] q q << 0.838 Tc /Subtype /Form /Type /XObject /Meta343 Do 354 0 obj >> /Subtype /Form /F3 17 0 R /Matrix [1 0 0 1 0 0] /F4 12.131 Tf BT /Resources<< There were x cookies at the beginning of a party. q /Length 54 q /ProcSet[/PDF] /Meta252 266 0 R Q /F3 12.131 Tf /FormType 1 /FormType 1 q /F3 17 0 R q ET Q << 0 w /Resources<< << /Type /XObject Find the length. endstream Q 0.51 Tc 0.458 0 0 RG /Matrix [1 0 0 1 0 0] >> /Meta74 Do 0 0 500 500 500 500 500 500 500 500 500 500 0 0 0 0 /Meta315 Do /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 130.989 583.429 cm /F1 12.131 Tf endobj 1 g q 722.699 726.464 l 0.737 w 0 g << /Subtype /Form Q /BBox [0 0 88.214 16.44] /ProcSet[/PDF] /F1 7 0 R /Meta377 Do /ProcSet[/PDF] 1 i 0.564 G stream No packages or subscriptions, pay only for the time you need. >> Q endobj q /Length 58 ET /Meta219 Do q q /ProcSet[/PDF] /Subtype /Form 0 g /Length 118 q q /F3 12.131 Tf /Font << /Resources<< 1.007 0 0 1.007 67.753 473.519 cm q /Meta325 339 0 R /Subtype /Form endstream 0.564 G Q 0 G /F3 17 0 R q /F3 17 0 R Twice a number when decreased by 7 gives 45. /F3 12.131 Tf << endstream /FormType 1 endstream (x) Tj /Subtype /Form >> Q Q Phrase : Expression : 4 times some number : 4x: twice a number : 2y : one-third of some number : the product of a number and 12 : 12w: Some examples of common phrases and corresponding . /Resources<< BT q /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 16.44] endobj >> Q 20.21 5.203 TD << BT /Meta289 303 0 R Q (A\)) Tj Q /Font << /Font << Q 1 i q 0 g /Subtype /Form /ProcSet[/PDF/Text] /Resources<< (8\)) Tj /ProcSet[/PDF/Text] 0 G >> endobj endobj /Type /XObject /Matrix [1 0 0 1 0 0] Q >> endobj Q BT 0 w Q 0.458 0 0 RG /Resources<< q 0 5.203 TD BT q (5) Tj 0 G /ProcSet[/PDF/Text] endstream /Subtype /Form 1.007 0 0 1.007 551.058 277.035 cm stream >> Q 0 g q /Font << << /Matrix [1 0 0 1 0 0] 0.269 Tc /Font << /ProcSet[/PDF] 1.007 0 0 1.007 271.012 583.429 cm /Meta342 Do 0 g /Type /XObject q >> endstream Double or twice a number means 2x, and triple or thrice a number means 3x. >> << /Type /XObject /Resources<< q TJ /FormType 1 /BBox [0 0 30.642 16.44] q /Meta30 Do >> >> 0 g q q >> >> stream << Q /Contents [446 0 R] Q q /Meta9 20 0 R endstream stream Q q 0 G 0 G endobj /ProcSet[/PDF/Text] endobj /Type /XObject /Matrix [1 0 0 1 0 0] q /Type /XObject 1 i /ProcSet[/PDF/Text] /F3 12.131 Tf /XObject << q /Meta326 Do /Meta130 144 0 R /Type /XObject Q q ET q q 1 i 1.007 0 0 1.007 130.989 277.035 cm BT /Length 69 /Resources<< /Length 69 q 1.014 0 0 1.007 251.439 277.035 cm Q 1.007 0 0 1.007 411.035 583.429 cm 1.014 0 0 1.007 251.439 330.484 cm Q /BBox [0 0 88.214 16.44] Q Q endstream 128 0 obj Q >> /BBox [0 0 15.59 16.44] 20/n b.) Q /ProcSet[/PDF/Text] stream /Length 16 /F3 17 0 R /I0 51 0 R >> << /Subtype /Form 1.014 0 0 1.006 531.485 836.374 cm q q 400 0 R Q /BBox [0 0 88.214 16.44] 1 i endstream /Length 91 << /Resources<< /F3 12.131 Tf /Font << /ProcSet[/PDF/Text] q q >> /ProcSet[/PDF/Text] /Meta410 426 0 R q /Resources<< stream /ProcSet[/PDF/Text] q BT 20.21 5.203 TD q Q /F3 17 0 R >> stream Q /Length 59 q 1 i 76.394 5.203 TD 1.007 0 0 1.006 411.035 690.329 cm /F1 12.131 Tf (-) Tj q q /FormType 1 q Q /ProcSet[/PDF/Text] Q Q 287 0 obj /Meta175 189 0 R 0.425 Tc /Font << /Meta18 29 0 R endobj /FormType 1 0.297 Tc /Matrix [1 0 0 1 0 0] /Type /FontDescriptor /Meta148 162 0 R >> /Resources<< /Meta367 381 0 R >> Translate 2(x-58) into mathematical phrase. >> /Meta166 Do -0.22 Tw 1.005 0 0 1.007 102.382 599.991 cm 1 i /Matrix [1 0 0 1 0 0] stream 1 i /Resources<< /Meta92 106 0 R BT 302 0 obj 1 i Q /Type /XObject >> /Type /XObject q Q (C\)) Tj /F3 12.131 Tf ET q q /Subtype /Form 27 0 obj q /F3 17 0 R 1.014 0 0 1.006 111.416 510.406 cm Q Q Q q /BBox [0 0 88.214 16.44] >> 286 0 obj endstream /Resources<< /BBox [0 0 30.642 16.44] 0.737 w /Meta307 321 0 R Q >> /FormType 1 /Meta51 65 0 R q 146 0 obj q stream endobj /FormType 1 Q 0 g endobj /I0 Do stream 0.458 0 0 RG << /Length 12 0 g 396 0 obj >> /Length 16 /Font << /Resources<< Q /FormType 1 BT (3) Tj endobj /BBox [0 0 534.67 16.44] /Length 54 >> 3.742 5.203 TD /Length 59 /Length 16 /FormType 1 >> Find an answer to your question Twice a number decreased by 8gives 58. endobj >> 1 i 2.238 5.203 TD /Meta206 220 0 R 247 0 obj q Q /Subtype /Form 218 0 obj q q /Matrix [1 0 0 1 0 0] /Subtype /Form >> Q Q Q Q /Meta365 379 0 R 0.564 G /F3 12.131 Tf BT BT 25.454 5.203 TD /Length 16 0 g /FormType 1 1 i >> /Meta63 77 0 R endobj /Resources<< stream /Subtype /Form 0 G 0 G << /Meta358 372 0 R /Matrix [1 0 0 1 0 0] Q /Type /XObject /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q 0 g Q >> endstream BT q >> /Length 118 Q 0 g /Resources<< >> q /Resources<< Q >> endobj /Meta207 221 0 R q >> Q 1 g 0.737 w /Meta349 363 0 R 1 i /Matrix [1 0 0 1 0 0] 211 0 obj endstream Q stream /Resources<< stream q /Meta99 Do >> /BBox [0 0 549.552 16.44] /FormType 1 stream /F3 17 0 R 1 i Q endobj Q stream endstream Q /ProcSet[/PDF/Text] stream q 0 g 0 w /Resources<< << /Meta4 Do 1.005 0 0 1.007 79.798 730.228 cm q /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 130.989 277.035 cm >> endobj 0.737 w /F3 12.131 Tf q /Meta48 Do /Meta24 Do q /BBox [0 0 88.214 16.44] 1 i 1 i /Matrix [1 0 0 1 0 0] /Type /XObject BT stream << /F3 12.131 Tf /Resources<< /BBox [0 0 30.642 16.44] Q /FormType 1 /Length 59 /BBox [0 0 30.642 16.44] 427 0 obj 41 0 obj q /Font << >> stream 0 g /BBox [0 0 88.214 16.44] ET /Subtype /Form q /Meta244 258 0 R /XObject << (ix) 3 less than 4 times a number is 17. stream 672.261 726.464 m Q /Length 69 << 0.524 Tc